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Lemma 4.1 extends obviously to arbitrary area-preserving twist maps, where the action functional replaces the length. Invariant circles with rational rotation number happen for a thin set of twist maps.
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Deformations of minimal periodic orbits.
A strictly convex piecewise
curve
,
parametrized by the arc length
is completely determined by its
radius of curvature
.
We will assume that
is piecewise continuous.
At each of the finite number of points of discontinuity as well as at
the end points of the curve, we assume the existence of the one-sided
limits
.
A closed convex, piecewise
curve is, by
our convention, a finite union of strictly convex
arcs and straight line
segments called flat arcs. Let
be the subset of
piecewise
caustics.
If
belongs to a flat arc of
or if
belongs to a strictly convex arc and
on at least one side,
we say that A is a flat point of
. When
belongs to a strictly convex arc, and
, we say that A is a
vertex or a corner point.
We will freely identify periodic orbits of the billiard map with polygons,
inscribed in T.
A periodic orbit, P is said to admit a deformation, if there exists a
continuous deformation
of periodic orbits P.
More precisely if
are the arclength
coordinates, we assume that
are continuous.
We will also consider one-sided deformations P(t),
, or
, assuming the same conditions, except the derivatives
at t=0 are one-sided.
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Remarks.
1) Let
be a billiard map, and let
be an invariant circle. Let
. If
, then
contains minimal periodic orbits of type (p,q). Periodic points,
, satisfy
. Typically, they are isolated.
2) If
, for a convex caustic
, then
the one-sided derivatives,
, exist, and are given by
eq. 5. The jumps of the derivative are due to the flat arcs of
.
If
is strictly convex, then f is
, and
is given by Eq. 5.
3) With the same assumptions as in the preceeding remark, let
be a periodic point, and let P be the corresponding
inscribed polygon (Figures 8,10).
Let
be strictly convex at the supporting points of P. If
, then the periodic orbit P consists of
hyperbolic points. If
, then the points
are parabolic. By Lemma 4.3, the condition that
P be parabolic is necessary for the existence of periodic deformations of P.
A stronger assertion holds: if P is not an isolated periodic orbit,
then P is parabolic.
If P is a hyperbolic periodic orbit, then it is a repelling
periodic orbit for the circle map if
, and an attracting periodic
orbit for the circle map if
(see Figure 11).
If P is parabolic, and isolated,
P may be repelling or attracting on each side independently. It is also possible
that
contains isolated periodic points, and nontrivial intervals of
periodic points as well (see Figure 11 b)).
There is a similar analysis of the one-sided derivatives of
,
and a natural extension of eq. 5.
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Oliver Knill