
Fall 2003
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Mathematics 1a
Introduction to Calculus
Course Head: Robin Gottlieb
Office: Science Center 430
Email: gottlieb@math.harvard.edu
Head CA: Eduardo Saverin
Email: saverin@fas.harvard.edu
Exams
Here are some
previous exams and solutions that should provide
a good review of the material covered to date.
Please note that not all exam problems
apply. Solutions for the Fall 2000 and Fall 1999
Exams have been posted. Solutions for the Fall
2002 and Spring 1998 Exams will be posted by
October 18. Students are encouraged to attempt the
practice exams before checking the solutions.
Midterm 1
Additional corrections to Fall 2002:
#1(a) lim x to 2 should be written two more times.
#1(c) Unlike the damped oscillations in part (d), these are getting wilder as x increases.
#2: if the explanation given in the corrections is not adequate, please see Ex 6 p. 137 in your text.
#3c arctan x would have two horizontal asymptotes.
#4. When you give a linearization, make sure that what you have is the equation of a line! L (x) = f(a) + f'(a) (x-a) or in this case
L(x) = f(25) + f'(25) (x-25). It is not necessary to use this "formula" in order to get the linear approximation. The correct answer is 5.1 as stated in the corrections.
#6: I would say that the velocity graph does NOT have a vertical asymptote at x=3, but rather a jump discontinuity.
Corrections to spring 1998:
# 1(d) False: let f(x) = 1/x and g(x) = 5/x.
The limit rule quoted is only true if both limits independently exist.
1(e) The statement is false but the reason given doesn't make sense. If the function is continuous from the left and right with the definitions stated then the function must be continous. However, the left and right hand limits could be different, or we could have the left and right hand limits equal but the function defined at c to be something entirely different.
#5: f'(2) is not 1. This says that as h approaches 0 the difference between f at 2+h and at 2 approaches -1. Try f(x) = 4 for x <2 and f(x) = 3 for x>2 for example.
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